|α+(α-1)+(α+1)|=2

Lösung

∣ α + (α - 1) + (α + 1) ∣ = 2

α = - \frac{2}{3} or α = \frac{2}{3}

Dezimale

α = - 0.66666 \dots, α = 0.66666 \dots

Schritte zur Lösung

∣ α + α - 1 + α + 1 ∣ = 2

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

α + α - 1 + α + 1 = - 2 or α + α - 1 + α + 1 = 2

α + α - 1 + α + 1 = - 2 or α + α - 1 + α + 1 = 2

α = - \frac{2}{3} or α = \frac{2}{3}

4 ∣ 3 x - 6 ∣ + 3 = 15

∣ 2 x + 2 ∣ = 13

∣ a ∣ - 3 = 8

∣ 2 x - 3 ∣ - 3 = 4 x^{4} x

∣ 8 - 5 v ∣ = 43