|x^2-x+1|=7

Lösung

x^{2} - x + 1 = 7

x = - 2 or x = 3

Schritte zur Lösung

x^{2} - x + 1 = 7

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

x^{2} - x + 1 = - 7 or x^{2} - x + 1 = 7

x^{2} - x + 1 = - 7 or x^{2} - x + 1 = 7

keine L \overset{o}{¨} sung or (x = - 2 or x = 3)

x = - 2 or x = 3

∣ 5 x + 1 ∣ = 2 x

∣ k + 1 ∣ = 5

∣ k + 1 ∣ = 2

∣ b + 9 ∣ - 3 = 3

2 ∣ b + 7 ∣ = 20