|x-1|-2>= =0

Lösung

∣ x - 1 ∣ - 2 \geq = 0

x = - 1 or x = 3

Schritte zur Lösung

∣ x - 1 ∣ - 2 = 0

Verschiebe

2

auf die rechte Seite

∣ x - 1 ∣ = 2

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

x - 1 = - 2 or x - 1 = 2

x - 1 = - 2 or x - 1 = 2

x = - 1 or x = 3

x^{2} + x - 2 = x + 3

17 = 3 ∣ z + 3 ∣ - 4

∣ x + 1 ∣ + 9 = 4

∣ x + 1 ∣ + 9 = 6

∣ 3 r - 5 ∣ = 14