What is the answer to (x-|3x+2|)^2=16 ?

The answer to (x-|3x+2|)^2=16 is x=-3/2 \lor x=1

Solve for x: (x-|3x+2|)^2=16

The solution is x=-3/2 \lor x=1

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(x - ∣ 3 x + 2 ∣)^{2} = 16

x = - \frac{3}{2} or x = 1

Decimal Notation

x = - 1.5, x = 1

Solution steps

(x - ∣ 3 x + 2 ∣)^{2} = 16

Find positive and negative intervals

x < - \frac{2}{3}, x \geq - \frac{2}{3}

Solve the inequality for each interval

x = - \frac{3}{2} or x = 1

∣ 5 x - 4 ∣ = 0

∣ 5 x - 4 ∣ = 8

∣ 2 x + 12 ∣ = 14

2 ∣ 2 x + 4 ∣ = 32

- 9.28 x^{2} + ∣ 9 x ∣ = 2

What is the answer to (x-|3x+2|)^2=16 ?
The answer to (x-|3x+2|)^2=16 is x=-3/2 \lor x=1
Solve for x: (x-|3x+2|)^2=16
The solution is x=-3/2 \lor x=1