ln(x^2)=0.7

Lösung

ln (x^{2}) = 0.7

x = e^{0.7}, x = - e^{0.7}

Dezimale

x = 1.41906 \dots, x = - 1.41906 \dots

Schritte zur Lösung

ln (x^{2}) = 0.7

Wende die log Regel an

x^{2} = e^{0.7}

Löse

x^{2} = e^{0.7} : x = e^{0.7}, x = - e^{0.7}

x = e^{0.7}, x = - e^{0.7}

lo g_{5} (x) = - 2

ln (x - 1) + ln (x + 1) = 0

0 = ln (x)

ln (x) + ln (x - 3) = 0

ln (x + 5) = ln (x - 1) - ln (x + 1)