log_{5}(2x+4)=2

Lösung

lo g_{5} (2 x + 4) = 2

x = \frac{21}{2}

Dezimale

x = 10.5

Schritte zur Lösung

lo g_{5} (2 x + 4) = 2

Wende die log Regel an

2 x + 4 = 25

Löse

2 x + 4 = 25 : x = \frac{21}{2}

x = \frac{21}{2}

lo g_{10} (3 x + 5) = 2

ln (x) = 9

ln (x) = e

ln (2) - ln (3 x + 2) = 1

2 lo g_{4} (x) - lo g_{4} (x - 1) = 1