log_{10}(2x-1)= 1/2

Lösung

lo g_{10} (2 x - 1) = \frac{1}{2}

x = \frac{10 + 1}{2}

Dezimale

x = 2.08113 \dots

Schritte zur Lösung

lo g_{10} (2 x - 1) = \frac{1}{2}

Wende die log Regel an

2 x - 1 = 10

Löse

2 x - 1 = 10 : x = \frac{10 + 1}{2}

x = \frac{10 + 1}{2}

lo g_{10} (x) = - 6

lo g_{10} (x) = 11

lo g_{10} (4 x) = 3

x = lo g_{2} (x)

lo g_{10} (2 x) = lo g_{10} (x - 5) + 2