log_{16}(3-x)=0.5

Lösung

lo g_{16} (3 - x) = 0.5

x = - 1

Schritte zur Lösung

lo g_{16} (3 - x) = 0.5

Wende die log Regel an

3 - x = 4

Löse

3 - x = 4 : x = - 1

x = - 1

ln (t - m) = k t + c

lo g_{10} (x^{2}) = - 10

so l v e f or y, ln (y - 1) - 2 = x + ln (x)

ln (x + 2) = ln (7 x)

ln (3 x + 6) = 5