|x-15|>6

Lösung

∣ x - 15 ∣ > 6

x < 9 or x > 21

Intervall-Notation

(- \infty, 9) \cup (21, \infty)

Schritte zur Lösung

∣ x - 15 ∣ > 6

Wende Absoluteregel an: Wenn

∣ u ∣ > a, a > 0

dann

u < - a

u > a

x - 15 < - 6 or x - 15 > 6

x - 15 < - 6 or x - 15 > 6

x < 9 or x > 21

∣ x - 2 ∣ + 10 = 12

3 = \frac{7}{2} (3 x - 4)

2 s^{2} + 19 s + 45 = 0

16 x^{2} + 10 x - 27 = - 6 x + 5

\frac{x}{6} = 8