What is the answer to log_{5}(x+12)-log_{5}(x+2)=1 ?

The answer to log_{5}(x+12)-log_{5}(x+2)=1 is x= 1/2

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log_{5}(x+12)-log_{5}(x+2)=1

lo g_{5} (x + 12) - lo g_{5} (x + 2) = 1

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

lo g_{5} (x + 12) - lo g_{5} (x + 2) = 1

Add

lo g_{5} (x + 2)

to both sides

lo g_{5} (x + 12) - lo g_{5} (x + 2) + lo g_{5} (x + 2) = 1 + lo g_{5} (x + 2)

Simplify

lo g_{5} (x + 12) = 1 + lo g_{5} (x + 2)

Apply log rules

x + 12 = 5 (x + 2)

Solve

x + 12 = 5 (x + 2) : x = \frac{1}{2}

x = \frac{1}{2}

Verify Solutions:

x = \frac{1}{2}

True

The solution is

x = \frac{1}{2}

6 ln (7 x + 6) - 14 = 10

lo g_{3} (9 x - 5) = lo g_{3} (5 x - 7)

lo g_{10} (3 x - 3) = 2

ln (9 ln (x)) = 0

6.8 = ln (\frac{x}{100})

What is the answer to log_{5}(x+12)-log_{5}(x+2)=1 ?
The answer to log_{5}(x+12)-log_{5}(x+2)=1 is x= 1/2
Solve for x: log_{5}(x+12)-log_{5}(x+2)=1
The solution is x= 1/2