log_{10}(x^2-9x)=1

Lösung

lo g_{10} (x^{2} - 9 x) = 1

x = 10, x = - 1

Schritte zur Lösung

lo g_{10} (x^{2} - 9 x) = 1

Wende die log Regel an

x^{2} - 9 x = 10

Löse

x^{2} - 9 x = 10 : x = 10, x = - 1

x = 10, x = - 1

3 + 7 \cdot lo g_{5} (x) = 25

0 = ln (x + 1)

ln (x - 8) + ln (x + 1) = ln (x - 24)

ln (X) = 4.6184

lo g_{5} (x + 7) - lo g_{5} (x - 1) = 1