5=log_{2}(x-1)

Lösung

5 = lo g_{2} (x - 1)

x = 33

Schritte zur Lösung

5 = lo g_{2} (x - 1)

Wende die log Regel an

32 = x - 1

Löse

32 = x - 1 : x = 33

x = 33

0.9 = ln (x)

lo g_{4} (x) = \frac{5}{2}

lo g_{10} (x - 5) = 0

ln (3 x) = 8.2

ln (x) - 3 = 0