log_{2}(6x+3)=4

Lösung

lo g_{2} (6 x + 3) = 4

x = \frac{13}{6}

Dezimale

x = 2.16666 \dots

Schritte zur Lösung

lo g_{2} (6 x + 3) = 4

Wende die log Regel an

6 x + 3 = 16

Löse

6 x + 3 = 16 : x = \frac{13}{6}

x = \frac{13}{6}

lo g_{3} (x + 2) = 1

3 lo g_{8} (x) = 2 lo g_{x} (8) + 5

0.26 = ln (y)

ln (2 x + 1) = 2 - ln (x)

lo g_{2} ((x + 3)^{2}) = 4