ln(2x-5)=2

Lösung

ln (2 x - 5) = 2

x = \frac{e ^{2} + 5}{2}

Dezimale

x = 6.19452 \dots

Schritte zur Lösung

ln (2 x - 5) = 2

Wende die log Regel an

2 x - 5 = e^{2}

Löse

2 x - 5 = e^{2} : x = \frac{e ^{2} + 5}{2}

x = \frac{e ^{2} + 5}{2}

ln (2 x + 1) = 3

ln (x - 6) + 2 ln (x) = ln (x - 30)

lo g_{2} (x + 3) + lo g_{2} (x) = 2

so l v e f or x, y = ln (3 x^{2})

lo g_{x} (8) = - \frac{1}{2}