log_{2}(x+2)=e

Lösung

lo g_{2} (x + 2) = e

x = 2^{e} - 2

Dezimale

x = 4.58088 \dots

Schritte zur Lösung

lo g_{2} (x + 2) = e

Wende die log Regel an

x + 2 = 2^{e}

Löse

x + 2 = 2^{e} : x = 2^{e} - 2

x = 2^{e} - 2

7 lo g_{4} (3 w + 1) + 4 = 25

x^{2} = e^{2 l n (x)}

3.65 = 5 - lo g_{10} (x)

ln (3 x + 1) = 7.492

- lo g_{10} (x) = 1.3