log_{10}(x-2)=1.258

Lösung

lo g_{10} (x - 2) = 1.258

x = 1 0^{1.258} + 2

Dezimale

x = 20.11340 \dots

Schritte zur Lösung

lo g_{10} (x - 2) = 1.258

Wende die log Regel an

x - 2 = 1 0^{1.258}

Löse

x - 2 = 1 0^{1.258} : x = 1 0^{1.258} + 2

x = 1 0^{1.258} + 2

lo g_{7} (10 x) + 20 = 0

lo g_{3} (x) = 2.2

lo g_{10} (x) = 0.7929 - 1

0 = lo g_{3} (x)

5 = lo g_{2} (x)