What is the answer to 6ln(5x-3)+12=0 ?

The answer to 6ln(5x-3)+12=0 is x=(1+3e^2)/(5e^2)

Solve for x: 6ln(5x-3)+12=0

The solution is x=(1+3e^2)/(5e^2)

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6 ln (5 x - 3) + 12 = 0

x = \frac{1 + 3 e ^{2}}{5 e ^{2}}

Decimal Notation

x = 0.62706 \dots

Solution steps

6 ln (5 x - 3) + 12 = 0

Move

12

to the right side

6 ln (5 x - 3) = - 12

Divide both sides by

6

ln (5 x - 3) = - 2

Apply log rules

5 x - 3 = \frac{1}{e ^{2}}

Solve

5 x - 3 = \frac{1}{e ^{2}} : x = \frac{1 + 3 e ^{2}}{5 e ^{2}}

x = \frac{1 + 3 e ^{2}}{5 e ^{2}}

Verify Solutions:

x = \frac{1 + 3 e ^{2}}{5 e ^{2}}

True

The solution is

x = \frac{1 + 3 e ^{2}}{5 e ^{2}}

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3^{2 l o g_{10} (x)} = x

4 lo g_{3} (3 x) = lo g_{3} (3 x^{4})

ln (x - 5) + ln (x + 2) = ln (x - 14)

What is the answer to 6ln(5x-3)+12=0 ?
The answer to 6ln(5x-3)+12=0 is x=(1+3e^2)/(5e^2)
Solve for x: 6ln(5x-3)+12=0
The solution is x=(1+3e^2)/(5e^2)