solvefor r,d=ln(1+rs)

Lösung

löse nach

r, d = ln (1 + rs)

r = \frac{e ^{d} - 1}{s}

Schritte zur Lösung

d = ln (1 + rs)

Wende die log Regel an

e^{d} = 1 + rs

Löse

e^{d} = 1 + rs : r = \frac{e ^{d} - 1}{s}

r = \frac{e ^{d} - 1}{s}

ln (r) = - 2

4 ln (x - 1) = - 8

3 lo g_{7} (1) = lo g_{7} (1^{n})

ln (x) = 3.11

ln (x) = 3.13