log_{10}(2565x)=7

Lösung

lo g_{10} (2565 x) = 7

x = \frac{2000000}{513}

Dezimale

x = 3898.63547 \dots

Schritte zur Lösung

lo g_{10} (2565 x) = 7

Wende die log Regel an

2565 x = 10000000

Löse

2565 x = 10000000 : x = \frac{2000000}{513}

x = \frac{2000000}{513}

2 = ln (3 + c)

p (a) (a - b (a) ln (p (a))) = 0

3 = 10 \cdot lo g_{10} (x)

10 lo g_{8} (x) = 5

1.13 = lo g_{2} (\frac{x}{32000})