What is the answer to (ln(x))^2-ln(x)=0 ?

The answer to (ln(x))^2-ln(x)=0 is x=e,x=1

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(ln(x))^2-ln(x)=0

(ln (x))^{2} - ln (x) = 0

x = e, x = 1

Decimal Notation

x = 2.71828 \dots, x = 1

Solution steps

(ln (x))^{2} - ln (x) = 0

Rewrite the equation with

ln (x) = u

(u)^{2} - u = 0

Solve

u^{2} - u = 0 : u = 1, u = 0

u = 1, u = 0

Substitute back

u = ln (x),

solve for

x

Solve

ln (x) = 1 : x = e

Solve

ln (x) = 0 : x = 1

x = e, x = 1

Verify Solutions:

x = e

True

, x = 1

True

The solutions are

x = e, x = 1

lo g_{10} (\frac{2 x + 1}{x - 1}) = 0

- \frac{7}{18} = ln (x) 7

\frac{1}{lo g _{2} ( x )} = 5

\frac{1}{lo g _{2} ( x )} = 1

lo g_{e} (\frac{5}{x}) = 0.868

What is the answer to (ln(x))^2-ln(x)=0 ?
The answer to (ln(x))^2-ln(x)=0 is x=e,x=1
Solve for x: (ln(x))^2-ln(x)=0
The solution is x=e,x=1