ln(x)=2.0353

Lösung

ln (x) = 2.0353

x = e^{2.0353}

Dezimale

x = 7.65454 \dots

Schritte zur Lösung

ln (x) = 2.0353

Wende die log Regel an

x = e^{2.0353}

50 = 12.036 ln (x) + 2.9211

lo g_{b} (1) = 0

323418 = - lo g_{10} (x)

lo g_{36} (a) = lo g_{2} (x)

12 = \frac{lo g _{2} ( t )}{0.05}