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Beliebt Algebra >

ln(10-0.9v^2)=e^{-27.642}

Lösung

ln (10 - 0.9 v^{2}) = e^{- 27.642}

Lösung

v = \frac{- e ^{\frac{1}{e ^{27.642}}} + 10}{0.9}, v = - \frac{- e ^{\frac{1}{e ^{27.642}}} + 10}{0.9}

+1

Dezimale

v = 3.16227 \dots, v = - 3.16227 \dots

Schritte zur Lösung

ln (10 - 0.9 v^{2}) = e^{- 27.642}

Wende die log Regel an

10 - 0.9 v^{2} = e^{\frac{1}{e ^{27.642}}}

Löse

10 - 0.9 v^{2} = e^{\frac{1}{e ^{27.642}}} : v = \frac{- e ^{\frac{1}{e ^{27.642}}} + 10}{0.9}, v = - \frac{- e ^{\frac{1}{e ^{27.642}}} + 10}{0.9}

v = \frac{- e ^{\frac{1}{e ^{27.642}}} + 10}{0.9}, v = - \frac{- e ^{\frac{1}{e ^{27.642}}} + 10}{0.9}

Graph

Beliebte Beispiele

lo g_{4} (x) = 8, x

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x + 5 ln (x - 1) = 3.46

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