ln(7x+8)=2

Lösung

ln (7 x + 8) = 2

x = \frac{e ^{2} - 8}{7}

Dezimale

x = - 0.08727 \dots

Schritte zur Lösung

ln (7 x + 8) = 2

Wende die log Regel an

7 x + 8 = e^{2}

Löse

7 x + 8 = e^{2} : x = \frac{e ^{2} - 8}{7}

x = \frac{e ^{2} - 8}{7}

lo g_{a} (\frac{1}{81}) = - 4

2 = lo g_{10} (\frac{s}{s})

- 2300 = - (8.314) (298) (ln (x))

6 lo g_{3} (x) - 7 = 17

ln (7 \cdot 7^{2 x} + 7) = 0