ln(x-2)=in^{12}-in(x+2)

解答

ln (x - 2) = i n^{12} - in (x + 2)

x = \frac{W ( \frac{in}{e ^{- i n^{12} + 4 in}} ) + 2 in}{in}

求解步骤

ln (x - 2) = i n^{12} - in (x + 2)

若

f (x) = g (x)

，则

a^{f (x)} = a^{g (x)}

e^{l n (x - 2)} = e^{i n^{12} - in (x + 2)}

化简

e^{l n (x - 2)} : x - 2

x - 2 = e^{i n^{12} - in (x + 2)}

解

x - 2 = e^{i n^{12} - in (x + 2)} : x = \frac{W ( \frac{in}{e ^{- i n^{12} + 4 in}} ) + 2 in}{in}

x = \frac{W ( \frac{in}{e ^{- i n^{12} + 4 in}} ) + 2 in}{in}

lo g_{3} ((x + 1) (x + 3)) = 1

lo g_{2} (lo g_{e} (x)) = 1

lo g_{e} (- \frac{x}{456}) = 1

lo g_{10} (v) = \frac{4.288}{2.3}

lo g_{10} (15 - 2) = 2 lo g_{10} (x)