log_{2}(5x+4)=1

Lösung

lo g_{2} (5 x + 4) = 1

x = - \frac{2}{5}

Dezimale

x = - 0.4

Schritte zur Lösung

lo g_{2} (5 x + 4) = 1

Wende die log Regel an

5 x + 4 = 2

Löse

5 x + 4 = 2 : x = - \frac{2}{5}

x = - \frac{2}{5}

so l v e f or n, lo g_{2} (n) = 1

6 lo g_{9} (x) - lo g_{3} (x) = 4

2 lo g_{2} (x - 3) = 4

3 ln (4 x) = 18

3 ln (4 x) = 13