2.1=(0.5)(14.5188)t^2

解

2.1 = (0.5) (14.5188) t^{2}

t = \frac{50 \frac{21}{10} 2}{3 4033}, t = - \frac{50 \frac{21}{10} 2}{3 4033}

十進法表記

t = 0.53784 \dots, t = - 0.53784 \dots

解答ステップ

2.1 = (0.5) (14.5188) t^{2}

辺を交換する

(0.5) (14.5188) t^{2} = 2.1

以下で両辺を割る

7.2594

t^{2} = \frac{2.1}{7.2594}

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

t = \frac{2.1}{7.2594}, t = - \frac{2.1}{7.2594}

\frac{2.1}{7.2594} = \frac{50 \frac{21}{10} 2}{3 4033}

- \frac{2.1}{7.2594} = - \frac{50 \frac{21}{10} 2}{3 4033}

t = \frac{50 \frac{21}{10} 2}{3 4033}, t = - \frac{50 \frac{21}{10} 2}{3 4033}