log_{10}(x)=-0.6338

Lösung

lo g_{10} (x) = - 0.6338

x = \frac{1}{1 0 ^{0.6338}}

Dezimale

x = 0.23238 \dots

Schritte zur Lösung

lo g_{10} (x) = - 0.6338

Wende die log Regel an

x = \frac{1}{1 0 ^{0.6338}}

lo g_{2} (- 5 x) = 4

3 ln (x - 2) = 18

e (x) = ln (x)

lo g_{3} (x + 7) - lo g_{3} (x + 1) = 3

lo g_{10} (x) = - 1.45