(x-yi)^2=-8-6i

解

(x - y i)^{2} = - 8 - 6 i

(x = 1, x = - 1, y = 3 y = - 3)

解答ステップ

(x - y i)^{2} = - 8 - 6 i

拡張

(x - y i)^{2} : (x^{2} - y^{2}) - 2 i x y

(x^{2} - y^{2}) - 2 i x y = - 8 - 6 i

複素数は, その実数部と虚数部が等しい場合にのみ等しくなるequation系として書き換える:

[x^{2} - y^{2} = - 8 - 2 x y = - 6]

[x^{2} - y^{2} = - 8 - 2 x y = - 6] : (x = 1, x = - 1, y = 3 y = - 3)

(x = 1, x = - 1, y = 3 y = - 3)