(x+y)+(x-y)i=5+5i

解答

(x + y) + (x - y) \cdot i = 5 + 5 \cdot i

x = 5, y = 0

求解步骤

(x + y) + (x - y) i = 5 + 5 i

将

(x + y) + (x - y) \cdot i

改写成标准复数形式:

(x + y) + (x - y) i

(x + y) + (x - y) i = 5 + 5 i

将

5 + 5 \cdot i

改写成标准复数形式:

5 + 5 i

(x + y) + (x - y) i = 5 + 5 i

复数仅在实部和虚部均相等时才相等改写为方程组:

[x + y = 5 x - y = 5]

[x + y = 5 x - y = 5] : x = 5, y = 0

x = 5, y = 0

5 x + 6 i = - 8 + 6

- 3 - 4 i = (a + bi)^{2}

5 x + (7 x - 2 y) i = 2 + 8 i

(3 + 4 i) (u + v i) = 5 - i

z^{2} - 2 z + 1 - i = 0