What is the answer to solvefor x,e^{2x-y}+e^{y-2x}=0 ?

The answer to solvefor x,e^{2x-y}+e^{y-2x}=0 is x=(ln(-e^{2y}))/4

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solvefor x,e^{2x-y}+e^{y-2x}=0

solve for

x, e^{2 x - y} + e^{y - 2 x} = 0

x = \frac{ln ( - e ^{2 y} )}{4}

Solution steps

e^{2 x - y} + e^{y - 2 x} = 0

Factor

e^{2 x - y} + e^{y - 2 x} : e^{- y - 2 x} (e^{4 x} + e^{2 y})

e^{- y - 2 x} (e^{4 x} + e^{2 y}) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

e^{- y - 2 x} = 0 or e^{4 x} + e^{2 y} = 0

Solve

e^{- y - 2 x} = 0 :

No Solution for

x \in R

Solve

e^{4 x} + e^{2 y} = 0 : x = \frac{ln ( - e ^{2 y} )}{4}

The solution is

x = \frac{ln ( - e ^{2 y} )}{4}

14 x y - 2 x λ = 0

100 - (- 6^{2})

\cdot 143 + 305 \cdot 70

\frac{4}{2}

- 1 \times (- 1)

What is the answer to solvefor x,e^{2x-y}+e^{y-2x}=0 ?
The answer to solvefor x,e^{2x-y}+e^{y-2x}=0 is x=(ln(-e^{2y}))/4