|x^2+2x-36|=12

Lösung

x^{2} + 2 x - 36 = 12

x = - 8 or x = - 6 or x = 4 or x = 6

Schritte zur Lösung

x^{2} + 2 x - 36 = 12

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

x^{2} + 2 x - 36 = - 12 or x^{2} + 2 x - 36 = 12

x^{2} + 2 x - 36 = - 12 or x^{2} + 2 x - 36 = 12

(x = - 6 or x = 4) or (x = - 8 or x = 6)

x = - 8 or x = - 6 or x = 4 or x = 6

s im pl i f y \frac{2 m ^{- 4}}{( 2 m ^{- 4} ) ^{3}}

4 p + 4 \geq 12

a^{2} - 9 a + 20 = 0

- 3 y^{2} + 5 y - 6 = 0

4 x - 3 = 2 x + 7