What is expand (x^2-3)(x^2+2x+1)(x-1)(x^2+3) ?

The solution to expand (x^2-3)(x^2+2x+1)(x-1)(x^2+3) is x^7+x^6-x^5-x^4-9x^3-9x^2+9x+9

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expand (x^2-3)(x^2+2x+1)(x-1)(x^2+3)

expand

(x^{2} - 3) (x^{2} + 2 x + 1) (x - 1) (x^{2} + 3)

x^{7} + x^{6} - x^{5} - x^{4} - 9 x^{3} - 9 x^{2} + 9 x + 9

Solution steps

(x^{2} - 3) (x^{2} + 2 x + 1) (x - 1) (x^{2} + 3)

Expand

(x^{2} - 3) (x^{2} + 2 x + 1) (x - 1) (x^{2} + 3) : (x^{4} - 9) (x^{2} + 2 x + 1) (x - 1)

= (x^{4} - 9) (x^{2} + 2 x + 1) (x - 1)

Apply FOIL method

(x^{4} - 9) (x - 1) : x^{5} - x^{4} - 9 x + 9

= (x^{5} - x^{4} - 9 x + 9) (x^{2} + 2 x + 1)

Distribute parentheses

= x^{5} x^{2} + x^{5} \cdot 2 x + x^{5} \cdot 1 - x^{4} x^{2} - x^{4} \cdot 2 x - x^{4} \cdot 1 - 9 x x^{2} - 9 x \cdot 2 x - 9 x \cdot 1 + 9 x^{2} + 9 \cdot 2 x + 9 \cdot 1

Simplify

x^{5} x^{2} + x^{5} \cdot 2 x + x^{5} \cdot 1 - x^{4} x^{2} - x^{4} \cdot 2 x - x^{4} \cdot 1 - 9 x x^{2} - 9 x \cdot 2 x - 9 x \cdot 1 + 9 x^{2} + 9 \cdot 2 x + 9 \cdot 1 : x^{7} + x^{6} - x^{5} - x^{4} - 9 x^{3} - 9 x^{2} + 9 x + 9

= x^{7} + x^{6} - x^{5} - x^{4} - 9 x^{3} - 9 x^{2} + 9 x + 9

(3 x - 5) (x^{2} + x + 5)

1 + \frac{1}{2 + \frac{1}{1 + 2}}

2 π + 2 π

- \frac{1}{4} \times 2

\frac{3}{4} \times 16

What is expand (x^2-3)(x^2+2x+1)(x-1)(x^2+3) ?
The solution to expand (x^2-3)(x^2+2x+1)(x-1)(x^2+3) is x^7+x^6-x^5-x^4-9x^3-9x^2+9x+9