-2x^2+6x+1=0

解答

- 2 x^{2} + 6 x + 1 = 0

x = - \frac{- 3 + 11}{2}, x = \frac{3 + 11}{2}

十进制

x = - 0.15831 \dots, x = 3.15831 \dots

求解步骤

- 2 x^{2} + 6 x + 1 = 0

使用求根公式求解

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 2 ) \cdot 1}{2 ( - 2 )}

6^{2} - 4 (- 2) \cdot 1 = 211

x_{1, 2} = \frac{- 6 \pm 2 11}{2 ( - 2 )}

将解分隔开

x_{1} = \frac{- 6 + 2 11}{2 ( - 2 )}, x_{2} = \frac{- 6 - 2 11}{2 ( - 2 )}

x = \frac{- 6 + 2 11}{2 ( - 2 )} : - \frac{- 3 + 11}{2}

x = \frac{- 6 - 2 11}{2 ( - 2 )} : \frac{3 + 11}{2}

二次方程组的解是:

x = - \frac{- 3 + 11}{2}, x = \frac{3 + 11}{2}

17 x^{2} = 12 x

f a c t or x^{3} y^{2} + x y^{2}

- (3 v + 1) + 7 (6 v + 6) = - 37

f a c t or 3 f (g + h) + (g + h)^{2}

(x - 3)^{2} - 5 (x - 3) = - 4