化简 (7+3i)+(-1-14i)

解答

化简

(7 + 3 i) + (- 1 - 14 i)

6 - 11 i

求解步骤

(7 + 3 i) + (- 1 - 14 i)

将复数的实部和虚部分组

(a + bi) + (c + d i) = (a + c) + (b + d) i

= (7 - 1) + (3 - 14) i

化简

(7 - 1) + (3 - 14) i : 6 - 11 i

= 6 - 11 i

f a c t or 6 x^{3} - 23 x^{2} - 6 x + 8

s im pl i f y \frac{2 ^{4}}{4 !}

f a c t or + 4 x^{2} - 9 y^{4}

e x p an d (x^{2} + 3 x + 2) (x + 8)

s im pl i f y - \frac{9}{4} + \frac{9}{2}