faktorisieren 6x^5-13x^4-46x^3+27x^2+110x+56

Lösung

faktorisieren

6 x^{5} - 13 x^{4} - 46 x^{3} + 27 x^{2} + 110 x + 56

(x + 1)^{2} (x - 2) (3 x + 4) (2 x - 7)

Schritte zur Lösung

6 x^{5} - 13 x^{4} - 46 x^{3} + 27 x^{2} + 110 x + 56

Wende den rationalen Nullstellentest an

= (x + 1) \frac{6 x ^{5} - 13 x ^{4} - 46 x ^{3} + 27 x ^{2} + 110 x + 56}{x + 1}

\frac{6 x ^{5} - 13 x ^{4} - 46 x ^{3} + 27 x ^{2} + 110 x + 56}{x + 1} = 6 x^{4} - 19 x^{3} - 27 x^{2} + 54 x + 56

= (x + 1) (6 x^{4} - 19 x^{3} - 27 x^{2} + 54 x + 56)

Faktorisiere

6 x^{4} - 19 x^{3} - 27 x^{2} + 54 x + 56 : (x + 1) (x - 2) (3 x + 4) (2 x - 7)

= (x + 1) (x + 1) (x - 2) (3 x + 4) (2 x - 7)

Wende Exponentenregel an:

aa = a^{2}

(x + 1) (x + 1) = (x + 1)^{2}

= (x + 1)^{2} (x - 2) (3 x + 4) (2 x - 7)

s im pl i f y \frac{1 7 ^{- 3} + 1 7 ^{- 5}}{1 7 ^{- 4}}

s im pl i f y \frac{2}{7} \times 3

s im pl i f y \frac{15}{4} - 3

s im pl i f y \frac{4}{5} - \frac{1}{9}

s im pl i f y x y \cdot x