faktorisieren x^4-6x^3+2x^2+26x+17

Lösung

faktorisieren

x^{4} - 6 x^{3} + 2 x^{2} + 26 x + 17

(x + 1)^{2} (x^{2} - 8 x + 17)

Schritte zur Lösung

x^{4} - 6 x^{3} + 2 x^{2} + 26 x + 17

Wende den rationalen Nullstellentest an

= (x + 1) \frac{x ^{4} - 6 x ^{3} + 2 x ^{2} + 26 x + 17}{x + 1}

\frac{x ^{4} - 6 x ^{3} + 2 x ^{2} + 26 x + 17}{x + 1} = x^{3} - 7 x^{2} + 9 x + 17

= (x + 1) (x^{3} - 7 x^{2} + 9 x + 17)

Faktorisiere

x^{3} - 7 x^{2} + 9 x + 17 : (x + 1) (x^{2} - 8 x + 17)

= (x + 1) (x + 1) (x^{2} - 8 x + 17)

Wende Exponentenregel an:

aa = a^{2}

(x + 1) (x + 1) = (x + 1)^{2}

= (x + 1)^{2} (x^{2} - 8 x + 17)

s im pl i f y 1^{\frac{5}{6}}

\frac{1}{7} \div \frac{1}{2}

s im pl i f y \frac{3}{3} + 2

s im pl i f y \frac{3}{7 - i}

s im pl i f y \frac{3}{( - 3 )}