faktorisieren x^4-2x^3-4x^2+2x+3

Lösung

faktorisieren

x^{4} - 2 x^{3} - 4 x^{2} + 2 x + 3

(x - 1) (x + 1)^{2} (x - 3)

Schritte zur Lösung

x^{4} - 2 x^{3} - 4 x^{2} + 2 x + 3

Wende den rationalen Nullstellentest an

= (x - 1) \frac{x ^{4} - 2 x ^{3} - 4 x ^{2} + 2 x + 3}{x - 1}

\frac{x ^{4} - 2 x ^{3} - 4 x ^{2} + 2 x + 3}{x - 1} = x^{3} - x^{2} - 5 x - 3

= (x - 1) (x^{3} - x^{2} - 5 x - 3)

Faktorisiere

x^{3} - x^{2} - 5 x - 3 : (x + 1) (x + 1) (x - 3)

= (x - 1) (x + 1) (x + 1) (x - 3)

Wende Exponentenregel an:

aa = a^{2}

(x + 1) (x + 1) = (x + 1)^{2}

= (x - 1) (x + 1)^{2} (x - 3)

s im pl i f y \frac{5}{1 + 2 i}

s im pl i f y - 0.6 \cdot 0.4

s im pl i f y 7 x - 2 (4 x - 5)

s im pl i f y \frac{2}{7} \times \frac{4}{5}

s im pl i f y 3 + - 25