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受欢迎的代数 >

b^2+sqrt(2)b-4=0

解答

b^{2} + 2 b - 4 = 0

解答

b = 2, b = - 22

+1

十进制

b = 1.41421 \dots, b = - 2.82842 \dots

求解步骤

b^{2} + 2 b - 4 = 0

使用求根公式求解

b_{1, 2} = \frac{- 2 \pm ( 2 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(2)^{2} - 4 \cdot 1 \cdot (- 4) = 32

b_{1, 2} = \frac{- 2 \pm 3 2}{2 \cdot 1}

将解分隔开

b_{1} = \frac{- 2 + 3 2}{2 \cdot 1}, b_{2} = \frac{- 2 - 3 2}{2 \cdot 1}

b = \frac{- 2 + 3 2}{2 \cdot 1} : 2

b = \frac{- 2 - 3 2}{2 \cdot 1} : - 22

二次方程组的解是:

b = 2, b = - 22

作图

流行的例子

36q^2-333q+81=0

36 q^{2} - 333 q + 81 = 0

roo t s s^{2} + 2 s + 10

4 x^{2} + 69 = 28 x

solvefor y,xy-3x+4x^2=7

so l v e f or y, x y - 3 x + 4 x^{2} = 7

4 (x + 1)^{2} - 7 = 45