What are the solutions to the equation -8p^2+800p-12800=0 ?

The solutions to the equation -8p^2+800p-12800=0 are p=20,p=80

Find the zeros of -8p^2+800p-12800=0

The zeros of -8p^2+800p-12800=0 are p=20,p=80

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- 8 p^{2} + 800 p - 12800 = 0

p = 20, p = 80

Solution steps

- 8 p^{2} + 800 p - 12800 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 800 \pm 80 0 ^{2} - 4 ( - 8 ) ( - 12800 )}{2 ( - 8 )}

80 0^{2} - 4 (- 8) (- 12800) = 480

p_{1, 2} = \frac{- 800 \pm 480}{2 ( - 8 )}

Separate the solutions

p_{1} = \frac{- 800 + 480}{2 ( - 8 )}, p_{2} = \frac{- 800 - 480}{2 ( - 8 )}

p = \frac{- 800 + 480}{2 ( - 8 )} : 20

p = \frac{- 800 - 480}{2 ( - 8 )} : 80

The solutions to the quadratic equation are:

p = 20, p = 80

3 (x - 7)^{2} - 22 = 26

- x^{2} - 3 x = 5 - 3 x

x^{2} - 3 x - 4 = 0

x^{2} - x - 20 = 0

8 x - 2 x^{2} = 1

What are the solutions to the equation -8p^2+800p-12800=0 ?
The solutions to the equation -8p^2+800p-12800=0 are p=20,p=80
Find the zeros of -8p^2+800p-12800=0
The zeros of -8p^2+800p-12800=0 are p=20,p=80