25t^2-40t+16=0

解

25 t^{2} - 40 t + 16 = 0

t = \frac{4}{5}

十進法表記

t = 0.8

解答ステップ

25 t^{2} - 40 t + 16 = 0

解くとthe二次式

t_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 25 \cdot 16}{2 \cdot 25}

(- 40)^{2} - 4 \cdot 25 \cdot 16 = 0

t_{1, 2} = \frac{- ( - 40 ) \pm 0}{2 \cdot 25}

t = \frac{- ( - 40 )}{2 \cdot 25}

\frac{- ( - 40 )}{2 \cdot 25} = \frac{4}{5}

t = \frac{4}{5}

二次equationの解:

t = \frac{4}{5}