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受欢迎的代数 >

-5z^2+9z+13=-6z^2

解答

- 5 z^{2} + 9 z + 13 = - 6 z^{2}

解答

z = \frac{- 9 + 29}{2}, z = \frac{- 9 - 29}{2}

+1

十进制

z = - 1.80741 \dots, z = - 7.19258 \dots

求解步骤

- 5 z^{2} + 9 z + 13 = - 6 z^{2}

将

6 z^{2}

para o lado esquerdo

z^{2} + 9 z + 13 = 0

使用求根公式求解

z_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 13 = 29

z_{1, 2} = \frac{- 9 \pm 29}{2 \cdot 1}

将解分隔开

z_{1} = \frac{- 9 + 29}{2 \cdot 1}, z_{2} = \frac{- 9 - 29}{2 \cdot 1}

z = \frac{- 9 + 29}{2 \cdot 1} : \frac{- 9 + 29}{2}

z = \frac{- 9 - 29}{2 \cdot 1} : \frac{- 9 - 29}{2}

二次方程组的解是:

z = \frac{- 9 + 29}{2}, z = \frac{- 9 - 29}{2}

作图

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