zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的代数 >

0=3t^2-18t+24

解答

0 = 3 t^{2} - 18 t + 24

解答

t = 4, t = 2

求解步骤

0 = 3 t^{2} - 18 t + 24

交换两边

3 t^{2} - 18 t + 24 = 0

使用求根公式求解

t_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 3 \cdot 24}{2 \cdot 3}

(- 18)^{2} - 4 \cdot 3 \cdot 24 = 6

t_{1, 2} = \frac{- ( - 18 ) \pm 6}{2 \cdot 3}

将解分隔开

t_{1} = \frac{- ( - 18 ) + 6}{2 \cdot 3}, t_{2} = \frac{- ( - 18 ) - 6}{2 \cdot 3}

t = \frac{- ( - 18 ) + 6}{2 \cdot 3} : 4

t = \frac{- ( - 18 ) - 6}{2 \cdot 3} : 2

二次方程组的解是:

t = 4, t = 2

作图

流行的例子

2 x^{2} - 18 = 3 x - 13

(2x+1)^2=x(3x+2)

(2 x + 1)^{2} = x (3 x + 2)

3 x^{2} + 18 x + 21 = 0

81 = π r^{2}

- 2 x^{2} + 4 x - 20 = 0