What are the solutions to the equation 0=-4t^2+40t+44 ?

The solutions to the equation 0=-4t^2+40t+44 are t=-1,t=11

Find the zeros of 0=-4t^2+40t+44

The zeros of 0=-4t^2+40t+44 are t=-1,t=11

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0 = - 4 t^{2} + 40 t + 44

t = - 1, t = 11

Solution steps

0 = - 4 t^{2} + 40 t + 44

Switch sides

- 4 t^{2} + 40 t + 44 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 ( - 4 ) \cdot 44}{2 ( - 4 )}

4 0^{2} - 4 (- 4) \cdot 44 = 48

t_{1, 2} = \frac{- 40 \pm 48}{2 ( - 4 )}

Separate the solutions

t_{1} = \frac{- 40 + 48}{2 ( - 4 )}, t_{2} = \frac{- 40 - 48}{2 ( - 4 )}

t = \frac{- 40 + 48}{2 ( - 4 )} : - 1

t = \frac{- 40 - 48}{2 ( - 4 )} : 11

The solutions to the quadratic equation are:

t = - 1, t = 11

6 x^{2} - 18 x - 24 = 81

x^{2} - 6 x + 18

x^{2} + 4 x = 6

x^{2} + 4 x = 5

3 x^{2} + 12 x = 7 x + 2

What are the solutions to the equation 0=-4t^2+40t+44 ?
The solutions to the equation 0=-4t^2+40t+44 are t=-1,t=11
Find the zeros of 0=-4t^2+40t+44
The zeros of 0=-4t^2+40t+44 are t=-1,t=11