What are the solutions to the equation roots x^2-6x+18 ?

The solutions to the equation roots x^2-6x+18 are x=3+3i,x=3-3i

Find the zeros of roots x^2-6x+18

The zeros of roots x^2-6x+18 are x=3+3i,x=3-3i

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roots

x^{2} - 6 x + 18

x = 3 + 3 i, x = 3 - 3 i

Solution steps

x^{2} - 6 x + 18

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 6 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 18 : 6 i

x_{1, 2} = \frac{- ( - 6 ) \pm 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 i}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 6 i}{2 \cdot 1}

x = \frac{- ( - 6 ) + 6 i}{2 \cdot 1} : 3 + 3 i

x = \frac{- ( - 6 ) - 6 i}{2 \cdot 1} : 3 - 3 i

The solutions to the quadratic equation are:

x = 3 + 3 i, x = 3 - 3 i

x^{2} + 4 x = 6

x^{2} + 4 x = 5

3 x^{2} + 12 x = 7 x + 2

4 x^{2} - 9 = 0

x^{2} + 4 x - 4

What are the solutions to the equation roots x^2-6x+18 ?
The solutions to the equation roots x^2-6x+18 are x=3+3i,x=3-3i
Find the zeros of roots x^2-6x+18
The zeros of roots x^2-6x+18 are x=3+3i,x=3-3i