What are the solutions to the equation 10x^2+15x+7=0 ?

The solutions to the equation 10x^2+15x+7=0 are x=-3/4+i(sqrt(55))/(20),x=-3/4-i(sqrt(55))/(20)

Find the zeros of 10x^2+15x+7=0

The zeros of 10x^2+15x+7=0 are x=-3/4+i(sqrt(55))/(20),x=-3/4-i(sqrt(55))/(20)

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10 x^{2} + 15 x + 7 = 0

x = - \frac{3}{4} + i \frac{55}{20}, x = - \frac{3}{4} - i \frac{55}{20}

Solution steps

10 x^{2} + 15 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 10 \cdot 7}{2 \cdot 10}

Simplify

1 5^{2} - 4 \cdot 10 \cdot 7 : 55 i

x_{1, 2} = \frac{- 15 \pm 55 i}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 15 + 55 i}{2 \cdot 10}, x_{2} = \frac{- 15 - 55 i}{2 \cdot 10}

x = \frac{- 15 + 55 i}{2 \cdot 10} : - \frac{3}{4} + i \frac{55}{20}

x = \frac{- 15 - 55 i}{2 \cdot 10} : - \frac{3}{4} - i \frac{55}{20}

The solutions to the quadratic equation are:

x = - \frac{3}{4} + i \frac{55}{20}, x = - \frac{3}{4} - i \frac{55}{20}

4 (x^{2} - 9) - 8 = - 19

b, \frac{b ^{2}}{2} - \frac{t ^{2}}{8} = 1

y, x^{2} - 3 x y + 2 y^{2} = 0

x, 80 = - 42 x - x^{2}

(2 y - 1)^{2} - 4 = 6 y - 1

What are the solutions to the equation 10x^2+15x+7=0 ?
The solutions to the equation 10x^2+15x+7=0 are x=-3/4+i(sqrt(55))/(20),x=-3/4-i(sqrt(55))/(20)
Find the zeros of 10x^2+15x+7=0
The zeros of 10x^2+15x+7=0 are x=-3/4+i(sqrt(55))/(20),x=-3/4-i(sqrt(55))/(20)