What are the solutions to the equation b^2-1/8 =(1/4)b ?

The solutions to the equation b^2-1/8 =(1/4)b are b= 1/2 ,b=-1/4

Find the zeros of b^2-1/8 =(1/4)b

The zeros of b^2-1/8 =(1/4)b are b= 1/2 ,b=-1/4

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b^{2} - \frac{1}{8} = (\frac{1}{4}) b

b = \frac{1}{2}, b = - \frac{1}{4}

Decimal Notation

b = 0.5, b = - 0.25

Solution steps

b^{2} - \frac{1}{8} = (\frac{1}{4}) b

Multiply both sides by

8

8 b^{2} - 1 = 2 b

Move

2 b

to the left side

8 b^{2} - 1 - 2 b = 0

Write in the standard form

a x^{2} + b x + c = 0

8 b^{2} - 2 b - 1 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 8 ( - 1 )}{2 \cdot 8}

(- 2)^{2} - 4 \cdot 8 (- 1) = 6

b_{1, 2} = \frac{- ( - 2 ) \pm 6}{2 \cdot 8}

Separate the solutions

b_{1} = \frac{- ( - 2 ) + 6}{2 \cdot 8}, b_{2} = \frac{- ( - 2 ) - 6}{2 \cdot 8}

b = \frac{- ( - 2 ) + 6}{2 \cdot 8} : \frac{1}{2}

b = \frac{- ( - 2 ) - 6}{2 \cdot 8} : - \frac{1}{4}

The solutions to the quadratic equation are:

b = \frac{1}{2}, b = - \frac{1}{4}

2 x - 3 = x^{2} - 2 x + 1

- x^{2} - 8

40 x^{2} + 5 x = 0

x^{2} + 4 x + 2.5 = 0

x^{2} - 17 x = - 72

What are the solutions to the equation b^2-1/8 =(1/4)b ?
The solutions to the equation b^2-1/8 =(1/4)b are b= 1/2 ,b=-1/4
Find the zeros of b^2-1/8 =(1/4)b
The zeros of b^2-1/8 =(1/4)b are b= 1/2 ,b=-1/4