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受欢迎的代数 >

1+2/(x+1)=(3x+7)/(x^2+10x+9)

解答

1 + \frac{2}{x + 1} = \frac{3 x + 7}{x ^{2} + 10 x + 9}

解答

x = - 4, x = - 5

求解步骤

1 + \frac{2}{x + 1} = \frac{3 x + 7}{x ^{2} + 10 x + 9}

乘以最小公倍数

(x + 1) (x + 9) + 2 (x + 9) = 3 x + 7

解

(x + 1) (x + 9) + 2 (x + 9) = 3 x + 7 : x = - 4, x = - 5

x = - 4, x = - 5

验证解

找到无定义的点（奇点）:

x = - 1, x = - 9

将不在定义域的点与解相综合:

x = - 4, x = - 5

作图

流行的例子

1-1/(x^2+x)=-x/(x+1)

1 - \frac{1}{x ^{2} + x} = - \frac{x}{x + 1}

1/x+1/(2x)= 1/5

\frac{1}{x} + \frac{1}{2 x} = \frac{1}{5}

x-(3x+5)/(x+2)= 1/(x+2)

x - \frac{3 x + 5}{x + 2} = \frac{1}{x + 2}

\frac{1}{6} + \frac{1}{y} = \frac{1}{3}

1+5/(x-2)= 2/(x^2-4)

1 + \frac{5}{x - 2} = \frac{2}{x ^{2} - 4}