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受欢迎的代数 >

1/x+1/(x+1)= 1/(x+2)

解答

\frac{1}{x} + \frac{1}{x + 1} = \frac{1}{x + 2}

解答

x = - 2 + 2, x = - 2 - 2

+1

十进制

x = - 0.58578 \dots, x = - 3.41421 \dots

求解步骤

\frac{1}{x} + \frac{1}{x + 1} = \frac{1}{x + 2}

乘以最小公倍数

(x + 1) (x + 2) + x (x + 2) = x (x + 1)

解

(x + 1) (x + 2) + x (x + 2) = x (x + 1) : x = - 2 + 2, x = - 2 - 2

x = - 2 + 2, x = - 2 - 2

验证解

找到无定义的点（奇点）:

x = - 1, x = 0, x = - 2

将不在定义域的点与解相综合:

x = - 2 + 2, x = - 2 - 2

作图

流行的例子

7/(x-4)-6/(x-2)=2

\frac{7}{x - 4} - \frac{6}{x - 2} = 2

(x^2+3x-18}{6x}=\frac{2-3x)/3

\frac{x ^{2} + 3 x - 18}{6 x} = \frac{2 - 3 x}{3}

solvefor t,y=(t-a)/(t+3)

so l v e f or t, y = \frac{t - a}{t + 3}

2 x - \frac{1}{x} - 1 = 0

solvefor y, 3/(3x+y)=1

so l v e f or y, \frac{3}{3 x + y} = 1