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受欢迎的代数 >

1/(x-3)+1/(x+4)= 9/8

解答

\frac{1}{x - 3} + \frac{1}{x + 4} = \frac{9}{8}

解答

x = 4, x = - \frac{29}{9}

+1

十进制

x = 4, x = - 3.22222 \dots

求解步骤

\frac{1}{x - 3} + \frac{1}{x + 4} = \frac{9}{8}

乘以最小公倍数

8 (x + 4) + 8 (x - 3) = 9 (x - 3) (x + 4)

解

8 (x + 4) + 8 (x - 3) = 9 (x - 3) (x + 4) : x = 4, x = - \frac{29}{9}

x = 4, x = - \frac{29}{9}

验证解

找到无定义的点（奇点）:

x = 3, x = - 4

将不在定义域的点与解相综合:

x = 4, x = - \frac{29}{9}

作图

流行的例子

(x^2+2x)/(x+4)= 8/(x+4)

\frac{x ^{2} + 2 x}{x + 4} = \frac{8}{x + 4}

(900)/((210+x))=36

\frac{900}{( 210 + x )} = 36

(24)/(x-8)+4=(20)/(x-8)

\frac{24}{x - 8} + 4 = \frac{20}{x - 8}

\frac{1}{x} = \frac{1}{3} + \frac{1}{6}

(x^2-9x+20)/(x^2-3x+4)=0

\frac{x ^{2} - 9 x + 20}{x ^{2} - 3 x + 4} = 0