2^{x-1}= 17/2

Lösung

2^{x - 1} = \frac{17}{2}

x = \frac{ln ( \frac{17}{2} )}{ln ( 2 )} + 1

Dezimale

x = 4.08746 \dots

Schritte zur Lösung

2^{x - 1} = \frac{17}{2}

Wende Exponentenregel an

(x - 1) ln (2) = ln (\frac{17}{2})

Löse

(x - 1) ln (2) = ln (\frac{17}{2}) : x = \frac{ln ( \frac{17}{2} )}{ln ( 2 )} + 1

x = \frac{ln ( \frac{17}{2} )}{ln ( 2 )} + 1

4 (3 e^{- x} x^{2} - e^{- x} x^{3}) = 0

8 1^{x - 2} = 2 7^{2 x}

3 e^{3 x} - e^{- x} = 0

2^{x + 1} = 1

3^{x} = 37